Optimal. Leaf size=106 \[ -a^{3/2} A \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )+\frac{3 a^2 B \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{8 \sqrt{b}}+\frac{1}{8} a \sqrt{a+b x^2} (8 A+3 B x)+\frac{1}{12} \left (a+b x^2\right )^{3/2} (4 A+3 B x) \]
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Rubi [A] time = 0.0940031, antiderivative size = 106, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.35, Rules used = {815, 844, 217, 206, 266, 63, 208} \[ -a^{3/2} A \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )+\frac{3 a^2 B \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{8 \sqrt{b}}+\frac{1}{8} a \sqrt{a+b x^2} (8 A+3 B x)+\frac{1}{12} \left (a+b x^2\right )^{3/2} (4 A+3 B x) \]
Antiderivative was successfully verified.
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Rule 815
Rule 844
Rule 217
Rule 206
Rule 266
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(A+B x) \left (a+b x^2\right )^{3/2}}{x} \, dx &=\frac{1}{12} (4 A+3 B x) \left (a+b x^2\right )^{3/2}+\frac{\int \frac{(4 a A b+3 a b B x) \sqrt{a+b x^2}}{x} \, dx}{4 b}\\ &=\frac{1}{8} a (8 A+3 B x) \sqrt{a+b x^2}+\frac{1}{12} (4 A+3 B x) \left (a+b x^2\right )^{3/2}+\frac{\int \frac{8 a^2 A b^2+3 a^2 b^2 B x}{x \sqrt{a+b x^2}} \, dx}{8 b^2}\\ &=\frac{1}{8} a (8 A+3 B x) \sqrt{a+b x^2}+\frac{1}{12} (4 A+3 B x) \left (a+b x^2\right )^{3/2}+\left (a^2 A\right ) \int \frac{1}{x \sqrt{a+b x^2}} \, dx+\frac{1}{8} \left (3 a^2 B\right ) \int \frac{1}{\sqrt{a+b x^2}} \, dx\\ &=\frac{1}{8} a (8 A+3 B x) \sqrt{a+b x^2}+\frac{1}{12} (4 A+3 B x) \left (a+b x^2\right )^{3/2}+\frac{1}{2} \left (a^2 A\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+b x}} \, dx,x,x^2\right )+\frac{1}{8} \left (3 a^2 B\right ) \operatorname{Subst}\left (\int \frac{1}{1-b x^2} \, dx,x,\frac{x}{\sqrt{a+b x^2}}\right )\\ &=\frac{1}{8} a (8 A+3 B x) \sqrt{a+b x^2}+\frac{1}{12} (4 A+3 B x) \left (a+b x^2\right )^{3/2}+\frac{3 a^2 B \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{8 \sqrt{b}}+\frac{\left (a^2 A\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{a}{b}+\frac{x^2}{b}} \, dx,x,\sqrt{a+b x^2}\right )}{b}\\ &=\frac{1}{8} a (8 A+3 B x) \sqrt{a+b x^2}+\frac{1}{12} (4 A+3 B x) \left (a+b x^2\right )^{3/2}+\frac{3 a^2 B \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{8 \sqrt{b}}-a^{3/2} A \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )\\ \end{align*}
Mathematica [A] time = 0.247058, size = 118, normalized size = 1.11 \[ \frac{1}{24} \left (-24 a^{3/2} A \tanh ^{-1}\left (\frac{\sqrt{a+b x^2}}{\sqrt{a}}\right )+\frac{9 a^{5/2} B \sqrt{\frac{b x^2}{a}+1} \sinh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{\sqrt{b} \sqrt{a+b x^2}}+\sqrt{a+b x^2} \left (32 a A+15 a B x+8 A b x^2+6 b B x^3\right )\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.006, size = 107, normalized size = 1. \begin{align*}{\frac{Bx}{4} \left ( b{x}^{2}+a \right ) ^{{\frac{3}{2}}}}+{\frac{3\,Bax}{8}\sqrt{b{x}^{2}+a}}+{\frac{3\,B{a}^{2}}{8}\ln \left ( x\sqrt{b}+\sqrt{b{x}^{2}+a} \right ){\frac{1}{\sqrt{b}}}}+{\frac{A}{3} \left ( b{x}^{2}+a \right ) ^{{\frac{3}{2}}}}-A{a}^{{\frac{3}{2}}}\ln \left ({\frac{1}{x} \left ( 2\,a+2\,\sqrt{a}\sqrt{b{x}^{2}+a} \right ) } \right ) +A\sqrt{b{x}^{2}+a}a \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.7431, size = 1094, normalized size = 10.32 \begin{align*} \left [\frac{9 \, B a^{2} \sqrt{b} \log \left (-2 \, b x^{2} - 2 \, \sqrt{b x^{2} + a} \sqrt{b} x - a\right ) + 24 \, A a^{\frac{3}{2}} b \log \left (-\frac{b x^{2} - 2 \, \sqrt{b x^{2} + a} \sqrt{a} + 2 \, a}{x^{2}}\right ) + 2 \,{\left (6 \, B b^{2} x^{3} + 8 \, A b^{2} x^{2} + 15 \, B a b x + 32 \, A a b\right )} \sqrt{b x^{2} + a}}{48 \, b}, -\frac{9 \, B a^{2} \sqrt{-b} \arctan \left (\frac{\sqrt{-b} x}{\sqrt{b x^{2} + a}}\right ) - 12 \, A a^{\frac{3}{2}} b \log \left (-\frac{b x^{2} - 2 \, \sqrt{b x^{2} + a} \sqrt{a} + 2 \, a}{x^{2}}\right ) -{\left (6 \, B b^{2} x^{3} + 8 \, A b^{2} x^{2} + 15 \, B a b x + 32 \, A a b\right )} \sqrt{b x^{2} + a}}{24 \, b}, \frac{48 \, A \sqrt{-a} a b \arctan \left (\frac{\sqrt{-a}}{\sqrt{b x^{2} + a}}\right ) + 9 \, B a^{2} \sqrt{b} \log \left (-2 \, b x^{2} - 2 \, \sqrt{b x^{2} + a} \sqrt{b} x - a\right ) + 2 \,{\left (6 \, B b^{2} x^{3} + 8 \, A b^{2} x^{2} + 15 \, B a b x + 32 \, A a b\right )} \sqrt{b x^{2} + a}}{48 \, b}, -\frac{9 \, B a^{2} \sqrt{-b} \arctan \left (\frac{\sqrt{-b} x}{\sqrt{b x^{2} + a}}\right ) - 24 \, A \sqrt{-a} a b \arctan \left (\frac{\sqrt{-a}}{\sqrt{b x^{2} + a}}\right ) -{\left (6 \, B b^{2} x^{3} + 8 \, A b^{2} x^{2} + 15 \, B a b x + 32 \, A a b\right )} \sqrt{b x^{2} + a}}{24 \, b}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 14.5079, size = 218, normalized size = 2.06 \begin{align*} - A a^{\frac{3}{2}} \operatorname{asinh}{\left (\frac{\sqrt{a}}{\sqrt{b} x} \right )} + \frac{A a^{2}}{\sqrt{b} x \sqrt{\frac{a}{b x^{2}} + 1}} + \frac{A a \sqrt{b} x}{\sqrt{\frac{a}{b x^{2}} + 1}} + A b \left (\begin{cases} \frac{\sqrt{a} x^{2}}{2} & \text{for}\: b = 0 \\\frac{\left (a + b x^{2}\right )^{\frac{3}{2}}}{3 b} & \text{otherwise} \end{cases}\right ) + \frac{B a^{\frac{3}{2}} x \sqrt{1 + \frac{b x^{2}}{a}}}{2} + \frac{B a^{\frac{3}{2}} x}{8 \sqrt{1 + \frac{b x^{2}}{a}}} + \frac{3 B \sqrt{a} b x^{3}}{8 \sqrt{1 + \frac{b x^{2}}{a}}} + \frac{3 B a^{2} \operatorname{asinh}{\left (\frac{\sqrt{b} x}{\sqrt{a}} \right )}}{8 \sqrt{b}} + \frac{B b^{2} x^{5}}{4 \sqrt{a} \sqrt{1 + \frac{b x^{2}}{a}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.19011, size = 135, normalized size = 1.27 \begin{align*} \frac{2 \, A a^{2} \arctan \left (-\frac{\sqrt{b} x - \sqrt{b x^{2} + a}}{\sqrt{-a}}\right )}{\sqrt{-a}} - \frac{3 \, B a^{2} \log \left ({\left | -\sqrt{b} x + \sqrt{b x^{2} + a} \right |}\right )}{8 \, \sqrt{b}} + \frac{1}{24} \, \sqrt{b x^{2} + a}{\left (32 \, A a +{\left (15 \, B a + 2 \,{\left (3 \, B b x + 4 \, A b\right )} x\right )} x\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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